0=-16f^2+4624

Solution for 0=-16f^2+4624 equation:

0=-16f^2+4624

We move all terms to the left:

0-(-16f^2+4624)=0

We add all the numbers together, and all the variables

-(-16f^2+4624)=0

We get rid of parentheses

16f^2-4624=0

a = 16; b = 0; c = -4624;
Δ = b2-4ac
Δ = 02-4·16·(-4624)
Δ = 295936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{295936}=544$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-544}{2*16}=\frac{-544}{32}
=-17
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+544}{2*16}=\frac{544}{32}
=17
$